x^2+3x-2068=0

Solution for x^2+3x-2068=0 equation:

x^2+3x-2068=0

a = 1; b = 3; c = -2068;
Δ = b2-4ac
Δ = 32-4·1·(-2068)
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8281}=91$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-91}{2*1}=\frac{-94}{2}
=-47
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+91}{2*1}=\frac{88}{2}
=44
$